Answer:
The maximum potential energy of the net, compared to its unstretched potential energy, is: [tex]E_{mn} -E_{un} = 8400J[/tex]
Explanation:
From the question we are told that
The weight of the man is [tex]W_m = 700 \ N[/tex]
The distance of the window to the net is [tex]d = 10 \ m[/tex]
The distance stretched by net is [tex]D = 2 \ m[/tex]
Generally from the of conservation energy , the total energy is conserved
This implies that
[tex]E_m__{i} + E_{un} = E_m__{f}} + E_{mn}[/tex]
Where [tex]E_m__{i}}[/tex] is the initial potential energy of the , man which is mathematically evaluated as
[tex]E_m__{i}} = W_m * d[/tex]
Substituting values
[tex]E_m__{i}} = 700 *10[/tex]
[tex]E_m__{i}} = 7000 \ J[/tex]
And [tex]E_{un}[/tex] is the unstretched potential energy of the net
And [tex]E_m__{f}}[/tex] is the final potential energy of the man which is mathematically evaluated as
[tex]E_m__{f}} = - W_m * D[/tex]
Substituting values
[tex]E_m__{f}} = - 700 * 2[/tex]
[tex]E_m__{f}} = - 1400[/tex]
The negative show that the direction of the man is against the direction of gravitational pull
And [tex]E_{mn}[/tex] is the maximum potential energy of the net when stretched
So the above equation becomes
[tex]7000 + E_{un} = - 1400 + E_{mn}[/tex]
So
[tex]E_{mn} -E_{un} = 7000 + 1400[/tex]
[tex]E_{mn} -E_{un} = 8400J[/tex]
