A rectangle has a perimeter of 58 inches. The length is five more than twice the width. Write and solve an equation to determine the width of the rectangle.

Respuesta :

Answer:

Equation of the width: [tex]2(2w + 5) + 2w = 58[/tex]

The width of the rectangle is 8 inches.

Step-by-step explanation:

A rectangle has two dimensions, the length(l) and the width(w).

The perimeter of the rectangle is:

[tex]P = 2l + 2w[/tex]

A rectangle has a perimeter of 58 inches.

This means that:

[tex]2l + 2w = 58[/tex]

The length is five more than twice the width.

This means that [tex]l = 2w + 5[/tex]

Equation to find the width:

[tex]2(2w + 5) + 2w = 58[/tex]

[tex]4w + 10 + 2w = 58[/tex]

[tex]6w = 48[/tex]

[tex]w = \frac{48}{6}[/tex]

[tex]w = 8[/tex]

The width of the rectangle is 8 inches.