The correct answer is option D) 24.0 ml.
Divide the number of moles of the analyte present by the original volume of the analyte. For example, if the original volume of the analyte was 500 mL, divide by 1000 mL per L to obtain 0.5 L. Divide 0.01 moles of analyte by 0.5 L to obtain 0.02 moles per liter. This is the concentration or molarity.
It is therefore possible to determine the concentration of acetic acid in vinegar by titrating the vinegar with a strong base such as an aqueous sodium hydroxide solution.
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