Answer:
331 g
Explanation:
Step 1: Write the balanced equation
N₂(g) + 3 H₂(g) → 2 NH₃(g)
Step 2: Calculate the moles corresponding to 400 g of ammonia
The molar mass of ammonia is 17.03 g/mol.
[tex]400g \times \frac{1mol}{17.03g} =23.5mol[/tex]
Step 3: Calculate the moles required of nitrogen
The molar ratio of N₂ to NH₃ is 1:2.
[tex]23.5molNH_3 \times \frac{1molN_2}{2molNH_3} =11.8molN_2[/tex]
Step 4: Calculate the mass corresponding to 11.8 moles of nitrogen
The molar mass of nitrogen is 28.01 g/mol.
[tex]11.8 mol \times \frac{28.01g}{mol} =331 g[/tex]
