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Boxes A and B contain some counters. Box A contains more counters than Box B. 3k counters in Box A and K+8 in Box B. What is the smallest possible value of K?

Respuesta :

pedrocarratore

Answer:

5

Step-by-step explanation:

The following expressions can be written for the number of counters in each box and the relationship between the number of counters in boxes A and B:

[tex]A=3k\\B=k+8\\A>B\\3k>k+8\\2k>8\\k>4[/tex]

Assuming that "k" has to be an integer greater than 4, the smallest possible value of "k" is 5

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