Respuesta :

zwinkyzcard
the common ratio for this one should be -2 because it;s an infinite geometry
caylus
Hello,

[tex]u_{1} =6\\ \sum_{i=0}^\infty\6*q^i=60=6* \dfrac{1}{1-q} \\ \dfrac{1}{1-q} =10\\ 1-q= \dfrac{1}{10} \\ -q= -\dfrac{9}{10} \\ \boxed{q= \dfrac{9}{10} } [/tex]

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