If an area of a rectangle with width x can be represented with the expression A(x)=x(14-x), what is the perimeter of the rectangle?
A.) 28
B.) 56
C.) 56-4x
D.) 4x+28
To solve for the perimeter first figure out the length and width from the formula of area for the rectangle A = LxW A = (14-X)•X L = (14-X) W = X P = 2L + 2W P = 2(14-X) + 2(X) P = 28 - 2X + 2X P = 28. The perimeter of the rectangle is A. 28.
