Answer:
The answer is the option D
[tex]\sqrt{30}\ in[/tex]
Step-by-step explanation:
we know that
In a right triangle
Applying the Pythagoras Theorem
[tex]c^{2} =a^{2}+b^{2}[/tex]
where
c is the hypotenuse
a and b are the legs
In this problem we have
[tex]c=6\ in\\a=\sqrt{6}\ in[/tex]
substitute and solve for b
[tex]6^{2} =(\sqrt{6})^{2}+b^{2}[/tex]
[tex]36 =6+b^{2}[/tex]
[tex]b^{2}=30[/tex]
[tex]b=\sqrt{30}\ in[/tex]
