Respuesta :
3m2 + 2p2 − 15
when m = 3 and p = 10.
3(3)^2+2(10)^2-15
3*9+2*100-15
27+200_15
227_15
212
when m = 3 and p = 10.
3(3)^2+2(10)^2-15
3*9+2*100-15
27+200_15
227_15
212
Answer:
[tex]212[/tex]
Explanation:
Given
m [tex]= 3[/tex]
p [tex]= 10[/tex]
The equation in the question is
[tex]3 m^2 + 2 p^2 -15[/tex]
In order to solve the above equation , we shall replace m and p with their n given values
On substituting "m" with [tex]3[/tex] and p with [tex]10[/tex] in above quadratic equation, we get -
[tex]3 (3)^2 + 2 (p)^2 -15\\3 * 9 + 2 * 100 - 15\\27 + 200 - 15\\212[/tex]