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In a certain Algebra 2 class of 28 students, 21 of them play basketball and 8 of them play baseball. There are 2 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?

Step-by-step explanation: What I did is i added 21 8 and 2 together and subtracted them by the amount of students which is 28. Then with that number/ 3 I divided by 28 which gave me the percentage .10714. I then rounded and ended with 11%. Im pretty sure this is the right answer if anyone thinks they know im wrong please say

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apitts8117 apitts8117 · Answer 2 · 2020-05-18T00:13:36+02:00

apitts8117 apitts8117

18-05-2020

Answer:

THE CORRECT ANSWER IS 3/28

Step-by-step explanation:

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PLEASE HELP I WILL MAKE BRAINLIST In a certain Algebra 2 class of 28 students, 21 of them play basketball and 8 of them play baseball. There are 2 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?

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PLEASE HELP I WILL MAKE BRAINLIST
In a certain Algebra 2 class of 28 students, 21 of them play basketball and 8 of them play baseball. There are 2 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?