On a recent trip to the convenience store, you picked up 4 gallons of milk, 6 bottles of water and 5 snack size bags of chips. You total bill before tax was $ 29.7. If a bottle of water costs twice as much as a bag of chips, and a gallon of milk costs $1.80 more than a bottle of water, how much does each item cost

Respuesta :

Answer:

Milk $3.60

Water $1.80

Chips $0.90.

Step-by-step explanation:

If w = cost of 1 bottle of water, m = cost of 1 gal of milk and c cost of 1 bag of chips we have.

4m + 6w + 5c  = 29.7

Also we have w = 2c and m = 1.8 + w.

From the first equation we have c = w/2.

So substituting for c and m in the initial equation we have:

4(1.8 + w) + 6w + 5(w/2) = 29.7

7.2 + 4w + 6w + 2.5w = 29.7

12.5w = 22.5

w = 1. 80.

So c = w/2 = 1.8/2 = 0.90.

and  m = 1.8 + 1.8 = 3.60.

The cost of bag of chips is $5.58 , bottle of water is $ 11.16 and gallon of milk is $12.96.

What is an Equation ?

An equation is a mathematical statement formed when two algebraic expressions are equated using an equal sign.

It is given that

4 gallons of milk, 6 bottles of water and 5 snack size bags of chips costs $29.7

Let the price of bag of chips is $x

Then

bottle of water , y costs twice as much as a bag of chips

y = 2x

a gallon of milk , z costs $1.80 more than a bottle of water

z = y +1.8

z = 2x +1.8

The equation that will be formed is

x + 2x + 2x +1.8 = 29.7

5x +1.8 = 29.7

5x = 27.9

x = $5.58

y = $11.16

z = $12.96

Therefore the cost of bag of chips is $5.58 , bottle of water is $ 11.16 and gallon of milk is $12.96.

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