Answer:
a) 0.144J
b) 0.12J
Explanation:
A 0.200 kg air-track glider moving at 1.20 m/s bumps into a 0.600 kg glider at rest. a.) Find the total kinetic energy after collision if the collision is elastic. b.) Find the total kinetic energy after collision if the collision is completely inelastic.
Given that
M1 = 0.2kg
M2 = 0.6kg
U1 = 1.2 m/s
Since both momentum and energy are conserved in elastic collisions, the total kinetic energy after collision will be
1/2M1U^2 + 1/2M2U^2
1/2 × 0.2 × 1.2^2 + 0
K.E = 0.144J
B) In elastic collision, only momentum is conserved
M1U1 + M2U2 = (M1 + M2)V
U2 = 0 since the object is at rest
0.2×1.2 + 0 = (0.2 + 0.6)V
0.24 = 0.8V
V = 0.24/0.8
V = 0.3 m/s
K.E = 1/2(M1+M2)V
K.E = 1/2 (0.2 + 0.6) × 0.3
K.E = 0.4 × 0.3
K.E = 0.12J
