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A circle with the equation (x + 4)2 + (y + 2)2 = 36 is reflected over the line x = 1. What is the equation of the image? (x + 4)2 + (y - 2)2 = 36 (x - 6)2 + (y + 2)2 = 36 (x + 6)2 + (y - 2)2 = 36 (x - 4)2 + (y + 2)2 = 36

Respuesta :

PunIntended

Answer:

B

Step-by-step explanation:

Currently, the graph looks like the attachment.

The centre of this circle is at (-4, -2), but when we flip it over the line x = 1 (the blue line on the picture), the centre will become ((1- -4) + 1, -2) = (6, -2).

Look for the equation [tex](x-h)^2+(y-k)^2=r^2[/tex] that matches this center. We want the center (h, k) to be (6, -2), so our equation should look something like:

[tex](x-6)^2+(y+2)^2=36[/tex]

The answer is B.

Ver imagen PunIntended
amna04352

Answer:

(x - 6)² + (y + 2)² = 36

Step-by-step explanation:

Centre before reflection: (-4,-2)

Centre after reflection:

(-4+5+5,-2) = (6,-2)

(x - 6)² + (y + 2)² = 36

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