Answer: The mass of water produced in the reaction is 97.2 grams
Explanation:
We are given:
Moles of calcium hydroxide = 2.70 moles
The chemical equation for the reaction of calcium hydroxide and HCl follows:
[tex]Ca(OH)_2+HCl\rightarrow CaCl_2+2H_2O[/tex]
By Stoichiometry of the reaction:
1 mole of calcium hydroxide produces 2 moles of water
So, 2.70 moles of calcium hydroxide will produce = [tex]\frac{2}{1}\times 2.70=5.40mol[/tex] of HCl
To calculate mass for given number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Molar mass of water = 18 g/mol
Moles of water = 5.40 moles
Putting values in above equation, we get:
[tex]5.40mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=(5.40mol\times 18g/mol)=97.2g[/tex]
Hence, the mass of water produced in the reaction is 97.2 grams
