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Lithium reacts with oxygen to form lithium
oxide according to the equation: 4Li + 0, →
2L1,0. If 27.8 g of Li react completely with
32.0 g of Oz, how many grams of Li, are
formed?​

Respuesta :

MathPhys

Answer:

59.6 g

Explanation:

4Li + O₂ → 2Li₂O

32.0 g O₂ × (1 mol O₂ / 32.0 g O₂) = 1.00 mol O₂

1.00 mol O₂ × (2 mol Li₂O / mol O₂) = 2.00 mol Li₂O

2.00 mol Li₂O × (29.8 g Li₂O / mol Li₂O) = 59.6 g Li₂O

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