Respuesta :
Answer:
0.0532 g Fe
Explanation:
Using the stoichiometry:
0.0257 g Al * (1 mol Al/26.98 g Al) * (2 mol Fe/2 mol Al) * (55.85 g Fe/1 mol Fe)
Doing the math, you'll get 0.0532 g Fe, which is letter C.
Answer:
0.0532 g Fe
Explanation:
Using the stoichiometry:
0.0257 g Al * (1 mol Al/26.98 g Al) * (2 mol Fe/2 mol Al) * (55.85 g Fe/1 mol Fe)
Doing the math, you'll get 0.0532 g Fe, which is letter C.