Answer:
We choose C
Step-by-step explanation:
the coordinates at 135° are at ([tex]\frac{-\sqrt{2} }{2}[/tex], [tex]\frac{\sqrt{2} }{2}[/tex] )
As we can see, the x coordinate of the point is negative and the y coordinate of it is positive.
So this point is located at the quadrant ii
From 135 ° to 315°, it is rotated 180°
=> Each coordinate (x,y) is changed to (-x,-y)
= ([tex]\frac{\sqrt{2} }{2}[/tex], [tex]-\frac{\sqrt{2} }{2}[/tex] ) the new coordinate is located in quadrant iii
We choose C
