Answer:
x = 0, x = - 3 and x = 9
Step-by-step explanation:
Given
f(x) = [tex]\frac{7}{2x(x+3)(x-9)}[/tex]
The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the values that x cannot be and if the numerator is non zero for these values then they are vertical asymptotes.
2x(x + 3)(x - 9) = 0
Equate each factor to zero and solve for x
2x = 0 ⇒ x = 0
x + 3 = 0 ⇒ x = - 3
x - 9 = 0 ⇒ x = 9
Thus the vertical asymptotes are x = 0, x = - 3, x = 9
