Answer:
a)
[tex]a=\frac{1}{180x^2}[/tex]
b)
[tex]b=-4+\frac{28}{x}[/tex]
c)
[tex]c=\frac{22x}{x-2}[/tex]
Step-by-step explanation:
a)
[tex](xa)6=\frac{1}{30x}[/tex]
To find the value of a, we make a the subject of the equation, therefore cross multiplying to get:
[tex]1=180x^2a\\a=\frac{1}{180x^2}[/tex]
b)
[tex]-4(x-7) = xb[/tex]
Making b the subject of formula in the equation:
[tex]-4x+28=xb\\b=\frac{-4x+28}{x}\\ b=-4+\frac{28}{x}[/tex]
c)
[tex](x-2)c = 22x\\[/tex]
Making c the subject of the equation:
[tex](x-2)c = 22x\\c=\frac{22x}{x-2}[/tex]
