Answer:
Two isosceles right triangles. [tex]p_{3} = (-9,-2)[/tex] and [tex]p_{3'} = (7,-2)[/tex]
Step-by-step explanation:
The length of one side is:
[tex]l_{1} = \sqrt{[-1 - (-1)]^{2}+[6 - (-2)]^{2}}[/tex]
[tex]l_{1} = 8[/tex]
An isosceles right has two sides of identical length, which are both legs and perpendicular to each other. There are two possibilities:
[tex]p_{3} = (-1 - 8, -2)[/tex]
[tex]p_{3} = (-9,-2)[/tex]
[tex]p_{3'} = (-1 + 8, -2)[/tex]
[tex]p_{3'} = (7,-2)[/tex]