Answer:
V = 0.63 L
Explanation:
To solve this problem, we need to use the Charle's law which is a law that involves temperature and volume, assuming we have a constant pressure. The problem do not state that the pressure is being altered, so we can safely assume that the pressure is constant (Maybe 1 atm).
Now, as the pressure is constant, the Charle's law is the following:
V₁ / T₁ = V₂ / T₂ (1) V is volume in Liter, and T is temperature in Kelvin.
Using this law with the given data, we solve for V₂:
V₂ = V₁T₂ / T₁
Before we use this expression, let's convert the temperatures to Kelvin:
T₁ = 19 + 273 = 292 K
T₂ = 250 + 273 = 523 K
Now, let's calculate the volume of the balloon:
V₂ = 0.35 * 523 / 292
Answer:
0.63L
Explanation:
V1 = 0.35L
T1 = 19°C = (19 + 273.15)K = 292.15K
V2 = ?
T2 = 250°C = (250 + 273.15)K = 523.15k
Applying Charle's law, the volume of a given mass of gas is directly proportional to its pressure provided temperature remains constant
V1 / T1 = V2 / T2
V2 = (V1 * T2) / T1
V2 = (0.35 * 523.15) / 292.15
V2 = 0.626L
V2 = 0.63L
