Answer:
Magnetic flux will be equal to [tex]5.43\times 10^{-3}weber[/tex]
Explanation:
It is given radius of circular loop r = 0.10 m
Area of circular loop [tex]A=\pi r^2[/tex]
[tex]A=3.14\times 0.10^2=0.0314m^2[/tex]
Magnetic field B = 0.20 T
Angle between plane of loop and magnetic field [tex]\Theta =30^{\circ}[/tex]
Magnetic flux will be equal to [tex]\Phi =BAcos\Theta[/tex]
[tex]\Phi =0.2\times 0.0314\times cos30^{\circ}=5.43\times 10^{-3}weber[/tex]
So magnetic flux will be equal to [tex]5.43\times 10^{-3}weber[/tex]
