Respuesta :
Answer:
Either x≈ -1.12 or x ≈0.45
Step-by-step explanation:
Using the quadratic formula to solve this, we will follow the steps below;
First, write down the quadratic formula;
x = -b ±√b² - 4ac /2a
From the question, the equation given is: 6x²+4x−3=0
comparing the equation given withe standard equation ax² + bx + c=0
a= 6 b= 4 and c = -3
We can now proceed to insert the values into the formula;
x = -4 ±√4² - 4(6)(-3) /2(6)
x = -4 ±√16+72 /12
x = -4 ±√88 /12
Either x = -4+√88 /12
x ≈0.45
OR
x = -4 -√88 /12
x≈ -1.12
Either x≈ -1.12 or x ≈0.45
Answer:
x1 = 0.45 and x2 = -1.12
Step-by-step explanation:
To solve the equation 6x2+4x−3=0 using the quadratic formula, we use the following equation:
x = [-b ± √(b2 - 4ac)] / 2a
Where a, b and c are coefficients of the quadratic equantion (in our case, a = 6, b = 4 and c = -3)
So we have that:
x1 = [-4 + √(16 + 72)] / 12 = (-4 + 9.3808) / 12 = 0.4484
x2 = [-4 - √(16 + 72)] / 12 = (-4 - 9.3808) / 12 = -1.1151
Rounding to nearest hundredth, we have x1 = 0.45 and x2 = -1.12
