Respuesta :
Answer:
95% confidence interval for the actual proportion of Meridian Township residents who are in favor of the tax increase is [0.5228 , 0.6972].
Step-by-step explanation:
We are given that the Township Board of Meridian Township randomly surveyed a group of residents and found that 61% are in favor of the tax increase.
The estimated standard error of sample proportion is 0.0445.
Firstly, the pivotal quantity for 95% confidence interval for the population proportion is given by;
P.Q. = [tex]\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ~ N(0,1)
where, [tex]\hat p[/tex] = sample proportion of residents in favor of the tax increase = 61%
n = sample of criminals
p = population proportion
Here for constructing 99% confidence interval we have used One-sample z proportion test statistics.
The 95% confidence interval for the actual proportion of Meridian Township residents who are in favor of the tax increase is given by;
95% Confidence interval for p = [tex]\hat p \pm Z_\frac{\alpha}{2} \times \sqrt{\frac{\hat p(1-\hat p)}{n} }[/tex]
Here, Standard error = [tex]\sqrt{\frac{\hat p(1-\hat p)}{n} }[/tex] = 0.0445
And [tex]\alpha[/tex] = significance level
So, [tex]Z_\frac{\alpha}{2} =Z_\frac{0.05}{2}[/tex] = 1.96
Hence, 95% Confidence interval for p = [tex]0.61 \pm 1.96 \times 0.0445[/tex]
= [[tex]0.61 -0.08722[/tex] , [tex]0.61 +0.08722[/tex]]
= [0.5228 , 0.6972]
Therefore, 95% confidence interval for the actual proportion of Meridian Township residents who are in favor of the tax increase is [0.5228 , 0.6972].
Also, the upper bound for the 95% confidence interval is 0.6971.