Answer:
The new temperature of the gas is 200 Celsius degrees.
Explanation:
Charles's Law consists of the relationship between the volume and temperature of a certain amount of ideal gas, which is maintained at a constant pressure, by means of a proportionality constant that is applied directly.
In this way, Charles's law is a law that says that the quotient that exists between volume and temperature will always have the same value:
[tex]\frac{V}{T} =k[/tex]
Assuming you have a certain volume of gas V1 that is at a temperature T1 at the beginning of the experiment, if you vary the volume of gas to a new value V2, then the temperature will change to T2, and it will hold:
[tex]\frac{V1}{T1} =\frac{V2}{T2}[/tex]
In this case:
Replacing:
[tex]\frac{20}{100} =\frac{40}{T2}[/tex]
Solving:
[tex]T2=\frac{40}{\frac{20}{100} }[/tex]
T2=200 °C
The new temperature of the gas is 200 Celsius degrees.
Answer:
473°C
Explanation:
We'll begin by analysing what was given from the question. This is illustrated below:
Initial temperature (T1) = 100°C
Initial volume (V1) = 20 L
Final volume (V2) = 40 L
Final temperature (T2) =?
Next, we shall be converting the temperature in celsius to Kelvin temperature. This is illustrated below:
Temperature (Kelvin) = temperature (celsius) + 273
Initial temperature (T1) = 100°C = 100°C + 273 = 373K
Next, we shall obtain the new temperature by applying the Charles' law equation. This is illustrated below:
V1/T1 = V2/T2
20/373 = 40/T2
Cross multiply to express in linear form
20 x T2 = 373 x 40
Divide both side by 20
T2 = (373 x 40) /20
T2 = 746K
Next, we shall be converting the new temperature obtained from Kelvin to celsius temperature. This is illustrated below:
Temperature (celsius) = Temperature (Kelvin) - 273
Temperature (celsius) = 746K - 273
Temperature (celsius) = 473°C
