Answer:
a) 2*10^14 electrons
Explanation:
To find the amount of electrons you take into account that:
[tex]1C=6.2415*10^{18}electrons[/tex]
by replacing this values in the factor C of the charge given by the exercise you obtain:
[tex]-32*10^{-6}C=-32*10^{-6}(6.2415*10^{18}electrons)\approx2*10^{14}electrons[/tex]
= 2*10*10^13 =20*10^13 electrons (you take the absolute value)
hence, the total number of electrons in a charge of 32*10^-6 C is 2*10^13 electrons
