Answer:
Spring is stretched by 6 cm.
Explanation:
We have given spring is stretched by 8 cm
So x = 8 cm = 0.08 m
Applied force F = 13 N
By hook's law [tex]F=Kx[/tex], here K is spring constant and x is stretched length of spring.
So [tex]13=K\times 0.08[/tex]
[tex]K=162.5N/m[/tex]
Now force F = 26 N
Again applying hook's law
[tex]26=162.5\times x[/tex]
x = 0.16 m = 16 cm
