Which equations can be used to determine the area of the irregular figure? Check all that apply.

A trapezoid has a base of 4 centimeters, height of 3 centimeters, and top side with a length of 2 centimeters.
A = one-half (3) (2) + 2 (3)
A = one-half (3) (4) + one-half (2) (3)
A = one-half (2) (3) (4)
A = 2 (3) (4)
A = one-half (3) (4) + 2 (3)
A = 3 (4) + 2 (3)

Respuesta :

Answer:

A and B

Step-by-step explanation:

The area of a trapezoid is denoted by: [tex]A=\frac{(b_1+b_2)h}{2}[/tex], where b_1 and b_2 are the bases and h is the height. Here, b_1 = 2, b_2 = 4, and h = 3. If we plug these values in, we get:

[tex]A=\frac{(b_1+b_2)h}{2}[/tex]

[tex]A=\frac{(2+4)*3}{2}=\frac{3*2}{2} +\frac{3*4}{2} =\frac{3*2}{2} +3*2[/tex]

Thus, only the first two choices work.

Hope this helps!

Answer:

A. A = one-half (3) (2) + 2 (3)

B. A = one-half (3) (4) + one-half (2) (3)

Step-by-step explanation:

Area of a trapezoid:

½(sum of // sides) × height

½(4 + 2)(3)

½(4)(3) + ½(2)(3)

(2)(3) + ½(2)(3)