Answer:
H = 0.2c J/Kg°C
Explanation:
m= 20g= 0.02kg, c=?, ∆t = 33-23= 10
H= mc∆t = 0.02×c×10= 0.2c J/kg°C
Answer:
q = 836 J
Explanation:
The amount of heat required to raise 20 grams of an unknown substance from 23° Celsius to 33° Celsius can be computed below
The specific heat capacity of the substance is not given, so let us assume the specific heat capacity of the substance is 4.18J/g°C.
q = mcΔt
where
q = amount of heat energy
m = mass
c = specific heat capacity
Δt = change in temperature
Δt = 33°C - 23°C = 10°C
q = mcΔt
q = 20 g × 4.18 J/g°C × 10° C
g cancel g and °C cancels °C . We are left with joules
q = 836 J
