Answer:
2.88 J/g°C
Explanation:
Mass calorimeter (Mc) = 50g
Temperature of calorimeter (T1) = 60°C
Mass of water (Mw) = 50g
Specific heat capacity of water (Cw) = 4.184 J/g°C
Specific heat capacity of calorimeter (Cc) = ?
Temperature of water (T2) = 20°C
Final temperature of the content (T3) = 36.6°C
Assuming no heat lose from the set up
Heat loss by copper calorimeter = heat gain by the water
Mc * Cc * (T1 - T3) = Mw * Cw * (T3 - T2)
50 * Cc * (60 - 36.3) = 50 * 4.184 * (36.3 - 20)
50 * Cc * 23.7 = 209.2 * 16.3
1185Cc = 3409.96
Cc = 3409.96 / 1185
Cc = 2.877 J/g°C
Cc = 2.88 J/g°C
The specific heat capacity of the copper calorimeter is 2.88 J/g°C
The heat capacity of the calorimeter will be "2.88 J/g°C".
According to the question,
Mass calorimeter, [tex]M_c[/tex] = 50 g
Calorimeter's temperature, [tex]T_1[/tex] = 60°C
Water's mass, [tex]M_w[/tex] = 50 g
Water's specific heat capacity, [tex]C_w[/tex] = 4.184 J/g°C
Water's temperature, T₂ = 20°C
Content's final temperature, T₃ = 36.3°C
We know,
Heat loss by copper calorimeter = Heat gain by the water
→ [tex]M_c[/tex] × [tex]C_c[/tex] × (T₁ - T₃) = [tex]M_w[/tex] × [tex]C_w[/tex] × (T₃ - T₂)
By substituting the values, we get
50 × [tex]C_c[/tex] × (60 - 36.3) = 50 × 4.184 × (36.3 - 20)
50 × [tex]C_c[/tex] × 23.7 = 209.2 × 16.3
[tex]C_c[/tex] = [tex]\frac{3409.96}{1185}[/tex]
= 2.88 J/g°C
Thus the response above is correct.
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