Answer:
Step-by-step explanation:
[tex]a)a^{3b}+a^{0}=(a^{b})^{3}+1\\\\=4^{3}+1\\\\= 64+1\\\\=65[/tex]
[tex]b)a^{-3b}-a^{0}=(a^{b})^{-3}\\=4^{-3}-1\\\\=\frac{1}{4^{3}}-1\\\\=\frac{1}{64}-1\\\\=\frac{1}{64}-\frac{64}{64}\\\\=\frac{-63}{64}[/tex]
[tex]c)(a^{0}-a^{b})^{-2}=(1-4)^{-2}\\\\=(-3)^{-2}\\\\=\frac{1}{(-3)^{2}}\\\\=\frac{1}{9}[/tex]
