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If 22.6 grams of an aqueous solution of zinc nitrate, Zn(NO3)2, contains 5.08 grams of zinc nitrate, what is the percentage by mass of zinc nitrate in the solution?

____% Zn(NO3)2

Respuesta :

keziakh004

Answer:

22.5%

Explanation:

To find percentage by mass, you divide the mass of the solute by the mass of the solvent.

5.08 g/22.6 g = 0.2248 = 22.5%

chase1posey410

Answer:

Mass of Zinc Nitrate = 5.08 gm

Mass of Zinc Nitrate + water = 22.6 gm

Mass percentage of zinc Nitrate = 5.08 g x 100 % / 22.6 g = 22.47 %

Explanation:

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