Respuesta :
Answer: a) [tex]I_2(g)+Cl_2(g)\rightarrow 2ICl(g)[/tex]: too close to decide.
b) [tex]2NOBr(g)\rightarrow 2NO(g)+Br_2(g)[/tex]: [tex]\Delta S[/tex] > 0.
c) [tex]CO_2(g)+H_2(g)\rightarrow CO(g)+H_2O(g)[/tex]: too close to decide.
d) [tex]2H_2O_2(l)\rightarrow 2H_2O(l)+O_2(g)[/tex]: [tex]\Delta S[/tex] > 0.
Explanation:
Entropy is the measure of randomness or disorder of a system. If a system moves from an ordered arrangement to a disordered arrangement, the entropy is said to decrease and vice versa.
For the reaction:
a) [tex]I_2(g)+Cl_2(g)\rightarrow 2ICl(g)[/tex]
In this reaction 2 moles of gaseous reactants are converting to 2 moles of gaseous products. Thus [tex]\Delta S[/tex] is too close to decide.
b) [tex]2NOBr(g)\rightarrow 2NO(g)+Br_2(g)[/tex]
In this reaction 2 moles gaseous reactants is getting converted to 3 moles of gaseous products. Thus the randomness will increase and hence entropy will also increase.Thus [tex]\Delta S[/tex] > 0.
c) [tex]CO_2(g)+H_2(g)\rightarrow CO(g)+H_2O(g)[/tex]
In this reaction 2 moles of gaseous reactants are converting to 2 moles of gaseous products. Thus [tex]\Delta S[/tex] is too close to decide.
d) [tex]2H_2O_2(l)\rightarrow 2H_2O(l)+O_2(g)[/tex]
In this reaction 2 moles liquid reactants is getting converted to 2 moles of liquid and 1 mole of gaseous products. Thus the randomness will increase and hence entropy will also increase.Thus [tex]\Delta S[/tex] > 0.
