Answer:
a) The expression for the Bohr radius is
[tex]r=\frac{n^{2} a_{o} }{z}[/tex] with a₀ = 0.5 A⁰
b) r = 0.5 A⁰
c) r = 0.25 A⁰
d) The probability is:
[tex]P=\int\limits^a_b {r^{2}\sqrt{\frac{1}{\pi a^{3} } }e^{-r/a}*\sqrt{\frac{2^{3} }{\pi a^{3} } }e^{-2r/a} } \, dr=0.04[/tex]
Explanation:
the solution is in the attached Word file