One day, after pulling down your window shade, you notice that sunlight is passing through a pinhole in the shade and making a small patch of light on the far wall. Having recently studied optics in your physics class, you're not too surprised to see that the patch of light seems to be a circular diffraction pattern. It appears that the central maximum is about 2 cmcm across, and you estimate that the distance from the window shade to the wall is about 5 mm.

Required:
Estimate the diameter of the pinhole.

Respuesta :

Complete Question

One day, after pulling down your window shade, you notice that sunlight is passing through a pinhole in the shade and making a small patch of light on the far wall. Having recently studied optics in your physics class, you're not too surprised to see that the patch of light seems to be a circular diffraction pattern. It appears that the central maximum is about 2 cm across, and you estimate that the distance from the window shade to the wall is about 5 m.

Required:

Estimate the diameter of the pinhole.  

Answer:

The diameter is  [tex]d =0.000336 m[/tex]

Explanation:

     From the question we are told that

            The central maxima is [tex]D= 2cm = \frac{2}{100} = 0.02m[/tex]

            The distance from the window shade is [tex]L = 5m[/tex]

     The  average wavelength of the  sun is mathematically evaluated as

                         [tex]\lambda_{ave } = \frac{\lambda_i + \lambda_f}{2}[/tex]

 Generally the visible light spectrum  has a wavelength  range  between  400 nm  to 700 nm  

        So  the initial wavelength of the sun is [tex]\lambda _i = 400nm[/tex]

           and the final wavelength is  [tex]\lambda_f = 700nm[/tex]

  Substituting this into the above equation

                 [tex]\lambda_{sun} = \frac{400nm +700nm}{2}[/tex]

                        [tex]= 550nm[/tex]

The diameter is evaluated as

              [tex]d = \frac{2.44 \lambda_{sun} L}{D}[/tex]

substituting values

              [tex]d = \frac{2.44 * 550*10^{-9} * 5 }{0.02}[/tex]

                [tex]d =0.000336 m[/tex]