Answer:
Probability of having a child with this genotype: CcFf is [tex]\frac{1}{4}[/tex]
Explanation:
Given -
Curly hair (C) is dominant to straight hair (c)
and
Freckles (F) is dominant to not having freckles (f)
Genotype of man heterozygous for curly hair and no freckles is Ccff
Genotype of woman with straight hair and heterozygous condition for freckles is ccFf
The cross is between Ccff and ccFf
The following offspring would be produced
Ccff and ccFf
Cf Cf cf cf
cF CcFf CcFf ccFf ccFf
cF CcFf CcFf ccFf ccFf
cf Ccff Ccff ccff ccff
cf Ccff Ccff ccff ccff
Genotype –
CcFf – 4 in number
ccFf - 4 in number
Ccff - 4 in number
ccff - 4 in number
Phenotype
CcFf – heterozygous for both the curly hairs and freckles
ccFf – straight hairs with heterozygous freckle condition
Ccff – Heterozygous curly hair with no freckles
ccff – staright hairs with no freckels
probability of having a child with this genotype: CcFf is
[tex]\frac{4}{16} \\\frac{1}{4}[/tex]
