A researcher wants to show the mean from population 1 is less than the mean from population 2 in matched-pairs data. If the observation from sample 1 are Xi and the observations from sample 2 are Yi, and di, = Xi - Yi, then the null hypothesis is H0 : \mu d+= 0 and the alternative hypothesis is H1 : \mu d____ 0.A researcher wants to show the mean from population 1 is less than the mean from population 2 in matched-pairs data. If the observations from sample 1 are Xi and the observations from sample 2 are Yi, and di = Xi - Yi, then the null hypothesis is H0 : \mu d = 0 and the alternative hypothesis is H1 : \mu d (choose answer below) 0.a. \neqb. <
c. >d. \leqe. \geq

This is because d is defined as the difference between the individuals of the sample from population 1 and the individuals of the sample from population 2. If the researcher wants to show the mean from population 1 is less than the mean from population 2 in matched-pairs data, he claims that d is less than 0 and this is his alternative hypothesis.

The equal sign is always used in the null hypothesis, never in the alternative hypothesis.

joaobezerra joaobezerra · Answer 2 · 2021-11-23T14:33:36+01:00

Making the desired test, it is found that:

The null hypothesis is: [tex]H_0: \mu_1 - \mu_2 \geq 0[/tex]
The alternative hypothesis is [tex]H_1: \mu_1 - \mu_2 < 0[/tex]

At the null hypothesis, we test if the mean from population 1 is not less than the mean from population 2 in matched-pairs data, that is, the subtraction of the mean of population 1 by the mean of population 2 is at least 0:

[tex]H_0: \mu_1 - \mu_2 \geq 0[/tex]

Then, at the alternative hypothesis, it is tested if the mean from population 1 is less than the mean from population 2, that is:

[tex]H_1: \mu_1 - \mu_2 < 0[/tex]

A similar problem is given at https://brainly.com/question/16767703