Answer:
13 units
Step-by-step explanation:
Let d be the distance between given points.
[tex] \therefore \: d = \sqrt{ {(5 - 0)}^{2} + ( - 4 - 8)^{2} } \\ \hspace{16 pt}= \sqrt{ {(5)}^{2} + ( - 12)^{2} } \\ \hspace{16 pt}= \sqrt{ 25 + 144 } \\ \hspace{16 pt}= \sqrt{ 169 } \\ \therefore \: d =13 \: units \\ [/tex]
