Answer:
Electric field, E = 0.114 N/C
Explanation:
Given that,
Length of the conducting rod, l = 34 cm = 0.34 m
The potential difference across the ends of the rod, [tex]V=39\ mV=39\times 10^{-3}\ V[/tex]
Let E is the magnitude of electric field inside the conductor. It can be calculated as :
[tex]E=\dfrac{V}{d}[/tex]
[tex]E=\dfrac{39\times 10^{-3}}{0.34}[/tex]
E = 0.114 N/C
So, the  magnitude of the electric field inside the conductor is 0.114 N/C. Hence, this is the required solution.
