Respuesta :

luciocravero
when a quadrilateral is inscriptible the opposite angles are supplementary       
So:   A + C = 180°
X + 20° + 110° = 180°
Then:   
                X = 50°
calculista
we know that
In any quadrilateral where the vertices are on the circumference of a circle, the opposite angles add up to [tex]180[/tex] degrees. 

So,
 in this problem
[tex](x+20) + 110 = 180 \\ x+130=180 \\ x=180-130 \\ x=50degrees[/tex]

therefore

the answer is
[tex]x=50degrees[/tex]

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