Respuesta :
[tex]\dfrac{x-6}{x^2-7x+6}=\dfrac{x-6}{x^2-x-6x+6}=\dfrac{x-6}{x(x-1)-6(x-1)}\\\\=\dfrac{x-6}{(x-1)(x-6)}=\dfrac{1}{x-1}\to\fbox{B.}\\\\\\12(x-5)+7x(x-5)=(x-5)(12+7x)\to\fbox{A.}[/tex]
(x-6) (x-6)
--------------- = ----------------- = 1/(x-1) so choice B. is right sure
x^2 -7x +6 (x-6)(x-1)
hope helped
--------------- = ----------------- = 1/(x-1) so choice B. is right sure
x^2 -7x +6 (x-6)(x-1)
hope helped