Answer:
(1) 92.92 unit (2) 500 unit²
Step-by-step explanation:
(1) Perimeter of the given hexagon ABCDEF will be
= Sum of length of all sides
= AB + BC + CD + DE + EF + FA
=[tex]10+(\sqrt{10^{2}+10^{2}})+\sqrt{10^{2}+10^{2}}+10+\sqrt{20^{2}+10^{2}}+\sqrt{20^{2} +10^{2} }[/tex]
= [tex]20+10\sqrt{2} +10\sqrt{2}+10+10\sqrt{(2+1)}+10\sqrt{(2+1)}[/tex]
= [tex](30+20\sqrt{2}+20\sqrt{3})[/tex]
= 30 + 28.28 + 34.64
= 92.92 unit
(2) Area of hexagon = Area of ΔAEF + Area of rectangle ABDE + Area of ΔBCD
= [tex]\frac{1}{2} (20)(20)+(20)(10)+\frac{1}{2}(20)(10)[/tex]
= 200 + 200 + 100
= 500 unit²
Answer:
He is wrong about the 92.92 500 was correct
Step-by-step explanation:
