what is the final amount of $3050.00 that is put into a savings account with 8% interest rate for 25 years, if the interest is compounded 4 times per year?

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The formula required is:
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]
where A is the amount after t years of the principal P invested at an annual interest rate r (expressed as a decimal fraction) compounded n times per year.
Plugging in the given values, we get:
[tex]A=3050(1+\frac{0.08}{4})^{(4\times25)}=22,096.17[/tex]
The final amount is $22,096.17

$22,096.17

Further explanation

Given:

  • The initial amount = $3,050.00
  • Time = 25 years
  • Interest rate = 8%, therefore 8% equal to 0.08
  • Compounded n = 4 times per year

Question:

What is the final amount?

The Process:

Compound interest is the interest earned from the initial amount and the interest earned previously. The formula for the balance A of the savings with compound interest is

[tex]\boxed{ \ A = P(1 + \frac{r}{n})^{nt} \ }[/tex]

  • P = principal (initial amount)
  • r = annual interest rate (in decimal form)
  • t = time (in years)
  • n = the number of periods of interest is compounded per year

Let us calculate the final amount.

[tex]\boxed{ \ A = 3,050(1 + \frac{0.08}{4})^{(4)(25)} \ }[/tex]

[tex]\boxed{ \ A = 3,050(1.02)^{100} \ }[/tex]

[tex]\boxed{ \ A = 3,050 \times 7.244646 \ }[/tex]

[tex]\boxed{ \ A = 22,096.1703 \approx 22,096.17 \ }[/tex]

Thus the final amount that is put into a savings account for 25 years is $22,096.17

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