Answer:
[tex]8181.23 \ cm^3[/tex]
Step-by-step explanation:
-A standard basketball has a spherical shape.
-Given the ball has a diameter of 25cm.
-The space available for air is equivalent to the ball's volume and is calculated as:
[tex]V=\frac{4}{3}\pi r^3, D=25\\\\=\frac{4}{3}\pi (D/2)^3\\\\\frac{4}{3}\pi (25/2)^3\\\\=8181.23\ cm^3[/tex]
Hence, the space available for air is [tex]8181.23 \ cm^3[/tex]
