Respuesta :

LammettHash

[tex]F(x)=\displaystyle\int_{x^2}^3\sin(t^2)\,\mathrm dt=-\int_3^{x^2}\sin(t^2)\,\mathrm dt[/tex]

By the fundamental theorem of calculus, differentiating gives

[tex]F'(x)=-\sin((x^2)^2)(2x)=-2x\sin(x^4)[/tex]

so the answer is A.

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