Answer:
Wavelength of sound in the pipe is 6.0 m
Explanation:
As we know that closed pipe is given to us so here at open end it will form antinode while at closed end it will form Node
Here we know that in closed pipes on odd harmonics will exist
so here for third harmonic we have
[tex]L = \frac{\lambda}{4} + \frac{\lambda}{2}[/tex]
where L = length of the pipe
so we have
[tex]4.5 = \frac{3\lambda}{4}[/tex]
[tex]\lambda = 6.0 m[/tex]
