20100280111349 20100280111349

31-03-2020
Chemistry

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A Sample of helium measuring 6l was kept at a pressure of 1.5atm. If pressure is doubled what would be its new volume?

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31-03-2020

Answer: 30.5

Explanation:

V1 = 61

P1 = 1.5

P2 = 2P1 ( 2X1.5) =3

V2 =?

Using Boyle's law; V1P1 = V2P2

[tex]\frac{V_{1}P_{1}}{P_{2}}=\frac{61(1.5)}{3} = \frac{91.5}{3}[/tex]

= 30.5

Therefore:

The new volume = 30.5

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