Answer:
a. 2.92*10^{-12}J/s
b. 4.82*10^{-12}J/s
Explanation:
You can use the expression for the rate of energy produce per unit time
[tex]E_i=\rho \frac{l}{S}I^2[/tex]
where
rho: resistivity
I: current
l: length
you can also use that
resistivity cooper=18.35*10^{-19}ohm*m
resistivity aluminum=30.31*10^{-19}ohm*m
(a) cooper
[tex]E_c=(18.35*10^{-19}\Omega m)\frac{1.0m}{\pi (0.002m)^2}(20.0A)=2.92*10^{-12}\frac{J}{s}[/tex]
(b) aluminum
[tex]E_c=(30.31*10^{-19}\Omega m)\frac{1.0m}{\pi (0.002m)^2}(20.0A)=4.82*10^{-12}\frac{J}{s}[/tex]
(c) Aluminum produced more energy due to that its density and its resistivity are greater than for cooper
hope this helps!!
