Answer:
[tex]\tau = 0.0219[/tex]
Explanation:
The time [tex]\tau[/tex] it takes for the voltage across the capacitor [tex]V_c[/tex] to go from 0 volts to 63% of the source voltage is given by the formula:
[tex]\tau= RC[/tex]
Where:
[tex]\tau=Time\hspace{3}constant\\R=Electrical\hspace{3}resistance\\C=Capacitance[/tex]
After [tex]5 \tau[/tex] the voltage has risen to 99% of its final value.
Therefore:
[tex]\tau =RC=300(73\times 10^{-6})=0.0219[/tex]
