A candle C sits between two parallel mirrors, a distance 0.2d from mirror 1. Here d is the distance between the mirrors. Multiple images of the candle appear in both mirrors. How far behind mirror 1 are the nearest three images of the candle in that mirror?

Question

31-03-2020
Physics

contestada

A candle C sits between two parallel mirrors, a distance 0.2d from mirror 1. Here d is the distance between the mirrors. Multiple images of the candle appear in both mirrors. How far behind mirror 1 are the nearest three images of the candle in that mirror?

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Xema8 Xema8 · Answer 1 · 2020-04-01T06:07:47+02:00

Answer:

Explanation:

First image will be at .2d distance because image distance = object distance .

first image in mirror 2 will be .8 d behind it so its distance from first mirror

= 1.8d .

This image will act as object for first mirror . So second image in mirror will be

1.8 d behind it.

First image in mirror 1 will act as object for mirror 2 so its image in mirror 2 will be 1.2d distance behind. It will act as object . So its image in mirror 1 will be 2.2d behind.

So image of first three image will be at .2d , 1.8d and 2.2d distance.